extract substring using regex in groovy

regex groovy regex-group
RicardoE picture RicardoE · Jul 9, 2013 · Viewed 51.2k times · Source

If I have the following pattern in some text:

def articleContent =  "<![CDATA[ Hellow World ]]>"

I would like to extract the "Hellow World" part, so I use the following code to match it:

def contentRegex = "<![CDATA[ /(.)*/ ]]>"
def contentMatcher = ( articleContent =~ contentRegex )
println contentMatcher[0]

However I keep getting a null pointer exception because the regex doesn't seem to be working, what would be the correct regex for "any peace of text", and how to collect it from a string?

Answer

tim_yates picture tim_yates · Jul 9, 2013

Try:

def result = (articleContent =~ /<!\[CDATA\[(.+)]]>/)[ 0 ]​[ 1 ]

However I worry that you are planning to parse xml with regular expressions. If this cdata is part of a larger valid xml document, better to use an xml parser

Related questions

Grails: Splitting a string that contains a pipe

I’m trying to split a String. Simple examples work: groovy:000> print "abc,def".split(","); [abc, def]===> null groovy:000> But instead of a comma, I need to split it on pipes, and I’m not getting the …

Read More
regex over multiple lines in Groovy

I have a multiple line string like following: END IF; EXECUTE IMMEDIATE ' CREATE INDEX #idx1 ON somename ( row_id, something)'; IF v_sys_error 0 THEN GOTO SQL_ERROR; END IF; I wish to capture the part in bold (…

Read More
Replace all occurrences in a String by using regex in groovy

When there are only one occurrence my code works: def result = "Text 1,1" def matches = (result =~ /^.+\s([0-9],[0-9])$/ ).with { m -> m.matches() ? result.replace(/${m[ 0 ][ 1 ]}/, 'X'+m[ 0 ][ 1 ]+'X') : result } assert "Text X,X" == matches How can I do …

Read More