conditional rendering in styled components

tom harrison picture tom harrison · Jan 29, 2018 · Viewed 66.9k times · Source

How can I use conditional rendering in styled-components to set my button class to active using styled-components in React?

In css I would do it similarly to this:

<button className={this.state.active && 'active'}
      onClick={ () => this.setState({active: !this.state.active}) }>Click me</button>

In styled components if I try to use '&&' in the classname it doesn't like it.

import React from 'react'
import styled from 'styled-components'

const Tab = styled.button`
  width: 100%;
  outline: 0;
  border: 0;
  height: 100%;
  justify-content: center;
  align-items: center;
  line-height: 0.2;
`

export default class Hello extends React.Component {
  constructor() {
    super()
    this.state = {
      active: false
    }  
    this.handleButton = this.handleButton.bind(this)
}

  handleButton() {
    this.setState({ active: true })
  }

  render() {
     return(
       <div>
         <Tab onClick={this.handleButton}></Tab>
       </div>
     )
  }}

Answer

Jo&#227;o Cunha picture João Cunha · Jan 29, 2018

You can simply do this

<Tab active={this.state.active} onClick={this.handleButton}></Tab>

And in your styles something like this:

const Tab = styled.button`
  width: 100%;
  outline: 0;
  border: 0;
  height: 100%;
  justify-content: center;
  align-items: center;
  line-height: 0.2;

  ${({ active }) => active && `
    background: blue;
  `}
`;