I have an application using React native where I am using react-navigation (5.2.9).
I built a Stack.Navigator where I've got my screens but I want the Footer component to be outside so it renders in all screens. The problem is, I can't navigate from the footer, which is what I need to do as the footer has a few buttons that should be changing the screen:
const Stack = createStackNavigator();
const App = () => {
return (
<Provider store={store}>
<NavigationContainer>
<Header />
<Stack.Navigator>
<Stack.Screen
name="Home"
component={HomeScreen}
options={{
headerShown: false
}}
/>
<Stack.Screen
name="Login"
component={LoginScreen}
options={{
headerShown: false
}}
/>
</Stack.Navigator>
<Footer />
</NavigationContainer>
</Provider>
);
};
How do I pass the navigation prop to the footer component?
Try this:
Create a new file named: RootNavigation.js
// RootNavigation.js
import * as React from 'react';
export const navigationRef = React.createRef();
export function navigate(name, params) {
navigationRef.current?.navigate(name, params);
}
// file where you have the navigation
import {navigationRef} from './path/to/RootNavigation';
<NavigationContainer ref={navigationRef}>
.....
<Footer />
</NavigationContainer>
And Footer.js should be something like this:
// Footer.js
import React from 'react';
import {View, Button} from 'react-native';
import * as RootNavigation from './path/to/RootNavigation';
const Footer= () => {
return (
<View>
<Button
title={'Go to'}
onPress={() =>
RootNavigation.navigate('screenName ', {userName: 'Lucy'})
}
/>
</View>
);
};
export default Footer;
For more info you can read the documentation. https://reactnavigation.org/docs/navigating-without-navigation-prop/