What are the R equivalents for these Python list comprehensions:
[(i,j) for i,j in zip(index, Values)]
[(i,j) for i,j in enumerate(Values)]
[(i,j) for i,j in enumerate(range(10,20))] %MWE, indexing or enumerating to
%keep up with the index, there may
%be some parameter to look this up
Example with Output
>>> [(i,j) for i,j in enumerate(range(10,20))]
[(0, 10), (1, 11), (2, 12), (3, 13), (4, 14), (5, 15), (6, 16), (7, 17), (8, 18), (9, 19)]
I have solved this problem earlier with some trick in R but cannot remember anymore, the first idea was itertools -pkg but I am hoping to find a more idiomatic way of doing things.
Answer
Answer for python enumerate:
In R, a list is ordered (see this answer). Thus, all you need is to index either keys (using names()[i]) or values (using [[i]]).
Using seq_along (alternatively can do for(i in 1:length(mylist)){...}):
> mylist <- list('a'=10,'b'=20,'c'=30)
> for (i in seq_along(mylist)){
+ print(paste(i,names(mylist)[i],mylist[[i]]))
+ }
[1] "1 a 10"
[1] "2 b 20"
[1] "3 c 30"
Answer for python zip:
See one of the above answers to mimic the list of tuples. My preference is towards a data frame as shown in BondedDust's answer:
> x <- 1:3
> y <- 4:6
> data.frame(x=x, y=y)
x y
1 1 4
2 2 5
3 3 6