One of the basic data types in R is factors. In my experience factors are basically a pain and I never use them. I always convert to characters. I feel oddly like I'm missing something.
Are there some important examples of functions that use factors as grouping variables where the factor data type becomes necessary? Are there specific circumstances when I should be using factors?
You should use factors. Yes they can be a pain, but my theory is that 90% of why they're a pain is because in read.table
and read.csv
, the argument stringsAsFactors = TRUE
by default (and most users miss this subtlety). I say they are useful because model fitting packages like lme4 use factors and ordered factors to differentially fit models and determine the type of contrasts to use. And graphing packages also use them to group by. ggplot
and most model fitting functions coerce character vectors to factors, so the result is the same. However, you end up with warnings in your code:
lm(Petal.Length ~ -1 + Species, data=iris)
# Call:
# lm(formula = Petal.Length ~ -1 + Species, data = iris)
# Coefficients:
# Speciessetosa Speciesversicolor Speciesvirginica
# 1.462 4.260 5.552
iris.alt <- iris
iris.alt$Species <- as.character(iris.alt$Species)
lm(Petal.Length ~ -1 + Species, data=iris.alt)
# Call:
# lm(formula = Petal.Length ~ -1 + Species, data = iris.alt)
# Coefficients:
# Speciessetosa Speciesversicolor Speciesvirginica
# 1.462 4.260 5.552
Warning message: In
model.matrix.default(mt, mf, contrasts)
:variable
Species
converted to afactor
One tricky thing is the whole drop=TRUE
bit. In vectors this works well to remove levels of factors that aren't in the data. For example:
s <- iris$Species
s[s == 'setosa', drop=TRUE]
# [1] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# [11] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# [21] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# [31] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# [41] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# Levels: setosa
s[s == 'setosa', drop=FALSE]
# [1] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# [11] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# [21] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# [31] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# [41] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# Levels: setosa versicolor virginica
However, with data.frame
s, the behavior of [.data.frame()
is different: see this email or ?"[.data.frame"
. Using drop=TRUE
on data.frame
s does not work as you'd imagine:
x <- subset(iris, Species == 'setosa', drop=TRUE) # susbetting with [ behaves the same way
x$Species
# [1] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# [11] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# [21] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# [31] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# [41] setosa setosa setosa setosa setosa setosa setosa setosa setosa setosa
# Levels: setosa versicolor virginica
Luckily you can drop factors easily with droplevels()
to drop unused factor levels for an individual factor or for every factor in a data.frame
(since R 2.12):
x <- subset(iris, Species == 'setosa')
levels(x$Species)
# [1] "setosa" "versicolor" "virginica"
x <- droplevels(x)
levels(x$Species)
# [1] "setosa"
This is how to keep levels you've selected out from getting in ggplot
legends.
Internally, factor
s are integers with an attribute level character vector (see attributes(iris$Species)
and class(attributes(iris$Species)$levels)
), which is clean. If you had to change a level name (and you were using character strings), this would be a much less efficient operation. And I change level names a lot, especially for ggplot
legends. If you fake factors with character vectors, there's the risk that you'll change just one element, and accidentally create a separate new level.