ggplot2: Define plot layout with grid.arrange() as argument of do.call()

CptNemo picture CptNemo · May 18, 2015 · Viewed 44.9k times · Source

I want to obtained an unbalanced grid of plots such as

require(ggplot2)
require(gridExtra)

df <- data.frame(value1 = rnorm(200),
                 value2 = rnorm(200),
                 value3 = rnorm(200),
                 value4 = rnorm(200))

p1 <- ggplot(df) + geom_density(aes(x=value1))
p2 <- ggplot(df) + geom_density(aes(x=value2))
p3 <- ggplot(df) + geom_density(aes(x=value3))
p4 <- ggplot(df) + geom_density(aes(x=value4))

grid.arrange(p1, arrangeGrob(p2,p3,p4, ncol=3), heights=c(2.5/4, 1.5/4), ncol=1)

enter image description here

but using a function

myplot <- function(i){
  p <- ggplot(df) + geom_density(aes_string(x=i))
  return(p)
}

and an lapply call

p <- lapply(c("value1","value2","value3","value4"), myplot)
do.call(grid.arrange, c(p))

In this case grid.arrange distribute the plots in a 2 by 2 matrix. But I want to obtain an unbalanced layout as with

grid.arrange(p1, arrangeGrob(p2,p3,p4, ncol=3), heights=c(2.5/4, 1.5/4), ncol=1)

Answer

baptiste picture baptiste · Jul 16, 2015

You can now do,

grid.arrange(p1,p2,p3,p4, layout_matrix = rbind(c(1,1,1),c(2,3,4)))