Averaging daily data into weekly data
I am wondering if there is a way to average daily data into weekly data. The dataframe that I call CADaily looks like this:
> CADaily[1:10, ]
Climate_Division Date Rain
885 1 1948-07-01 0.8750000
892 1 1948-07-02 2.9166667
894 1 1948-07-03 0.7916667
895 1 1948-07-04 0.4305556
898 1 1948-07-05 0.8262061
901 1 1948-07-06 0.5972222
904 1 1948-07-17 0.04166667
905 1 1948-07-18 0.08333333
907 1 1948-07-20 0.04166667
909 1 1948-07-22 0.12500000
910 1 1948-07-21 NA
My objective is similar to the aggregate function to find the average of the daily rain into weekly rain values base on the Date (of course) and the Climate_Division (ranges from 1 to 7). I was searching online and I came across a code that I was able to use but wasn't quite to par to my objective:
apply.weekly(xts(CADaily[,-2], order.by= CADaily[,2]), FUN = mean)
This does what I would like it to do, however my column Climate_Division is also averaged. I would simply like to average Rain only and order it based on the Climate_Division followed by Date. Is there a way that I can possibly do it as follows:
aggregate(CADaily, by =list(CADaily$Climate_Division, CADaily$Date), FUN = mean, na.rm = TRUE)
where Date is in some form of weeks? Or is there another way?
EDIT:
Dear All,
Thank you for your help. Perhaps using aggregate wasn't the best way to go about this as I originally thought. In terms of output, I wanted to obtain the weekly average of rain throughout the years of the data (1948 - 1995). In other words, I wanted to get a nice format that I can input into a time series that has the form of the date of the end of the week. The output that I am looking for (keeping in mind that there may exist NA values) is:
Climate_Division Date Rain
1 1948-07-03 1.527778
1 1948-07-10 0.6179946
1 1948-07-17 0.04166667
1 1948-07-24 0.08333333
...
1 1995-12-23 0.24513245
1 1995-12-30 0.12450545
Or is there a better way of expressing weekly data that is represented by dates?
Thank you for your help.
Answer
Updated answer
Based on the OP's update on the request, I modified the code to aggregate the data over the date of a defined day of each week (Saturday). This time I only use functions available in base R. It ignores NAs (if there are only NAs for a given End_of_Week-Climate_Division you get NaN, not a number).
# Data with another Climate division as example (same daily values and dates)
CADaily <-
structure(list(Climate_Division = c(1, 1, 1, 1, 1, 1, 1, 1, 1,
1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2), Date = structure(c(1L, 2L,
3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 1L, 2L, 3L, 4L, 5L, 6L, 7L,
8L, 9L, 10L), .Label = c("01/07/1948", "02/07/1948", "03/07/1948",
"04/07/1948", "05/07/1948", "06/07/1948", "17/07/1948", "18/07/1948",
"20/07/1948", "22/07/1948"), class = "factor"), Rain = c(0.875,
2.9166667, 0.7916667, 0.4305556, 0.8262061, 0.5972222, 0.04166667,
0.08333333, 0.04166667, 0.125, 0.875, 2.9166667, 0.7916667, 0.4305556,
0.8262061, 0.5972222, 0.04166667, 0.08333333, 0.04166667, 0.125
), week = c(27, 27, 27, 27, 27, 27, 29, 29, 29, 30, 27, 27, 27,
27, 27, 27, 29, 29, 29, 30)), .Names = c("Climate_Division",
"Date", "Rain", "week"), row.names = c(NA, 20L), class = "data.frame")
# Coerce to Date class
CADaily$Date <- as.Date(x=CADaily$Date, format='%d/%m/%Y')
# Extract day of the week (Saturday = 6)
CADaily$Week_Day <- as.numeric(format(CADaily$Date, format='%w'))
# Adjust end-of-week date (first saturday from the original Date)
CADaily$End_of_Week <- CADaily$Date + (6 - CADaily$Week_Day)
# Aggregate over week and climate division
aggregate(Rain~End_of_Week+Climate_Division, FUN=mean, data=CADaily, na.rm=TRUE)
# Output
# End_of_Week Climate_Division Rain
# 1 1948-07-03 1 1.52777780
# 2 1948-07-10 1 0.61799463
# 3 1948-07-17 1 0.04166667
# 4 1948-07-24 1 0.08333333
# 5 1948-07-03 2 1.52777780
# 6 1948-07-10 2 0.61799463
# 7 1948-07-17 2 0.04166667
# 8 1948-07-24 2 0.08333333
Additional operations
Also, using this code you can obtain results from additional aggregation functions, assuming the result is an atomic vector of the same length for every week-division pair.
# Aggregate over week and climate division, and show the total number of
# observations per week, the number of observations which represent missing
# values, the average, and the standard deviation.
aggregate(Rain~End_of_Week+Climate_Division, data=CADaily,
FUN=function(x) c(n=length(x),
NAs=sum(is.na(x)),
Average=mean(x, na.rm=TRUE),
SD=sd(x, na.rm=TRUE)))
# Output. You get NA for the standard deviation if there is only one observation.
# End_of_Week Climate_Division Rain.n Rain.NAs Rain.Average Rain.SD
# 1 1948-07-03 1 3.00000000 0.00000000 1.52777780 1.20353454
# 2 1948-07-10 1 3.00000000 0.00000000 0.61799463 0.19864151
# 3 1948-07-17 1 1.00000000 0.00000000 0.04166667 NA
# 4 1948-07-24 1 3.00000000 0.00000000 0.08333333 0.04166667
# 5 1948-07-03 2 3.00000000 0.00000000 1.52777780 1.20353454
# 6 1948-07-10 2 3.00000000 0.00000000 0.61799463 0.19864151
# 7 1948-07-17 2 1.00000000 0.00000000 0.04166667 NA
# 8 1948-07-24 2 3.00000000 0.00000000 0.08333333 0.04166667
Original answer
Try with the lubridate package. Load it, and then aggregate (kept for the record as part of the original answer, which reflected the OP's request to aggregate by week).
# Load lubridate package
library(package=lubridate)
# Set Weeks number. Date already of class `Date`
CADaily$Week <- week(CADaily$Date)
# Aggregate over week number and climate division
aggregate(Rain~Week+Climate_Division, FUN=mean, data=CADaily, na.rm=TRUE)
# Output
# Week Climate_Division Rain
# 1 27 1 1.07288622
# 2 29 1 0.05555556
# 3 30 1 0.12500000
# 4 27 2 1.07288622
# 5 29 2 0.05555556
# 6 30 2 0.12500000