Counting the number of rows of a series of csv files

Doug Fir picture Doug Fir · Jan 16, 2013 · Viewed 25k times · Source

I'm working through an R tutorial and suspect that I have to use one of these functions but I'm not sure which (Yes I researched them but until I become more fluent in R terminology they are quite confusing).

In my working directory there is a folder "specdata". Specdata contains hundreds of CSV files named 001.csv - 300.csv.

The function I am working on must count the total number of rows for an inputed number of csv files. So if the argument in the function is 1:10 and each of those files has ten rows, return 100.

Here's what I have so far:

complete <- function(directory,id = 1:332) {
    setpath <- paste("/Users/gcameron/Desktop",directory,sep="/")
    setwd(setpath)
    csvfile <- sprintf("%03d.csv", id)
    file <- read.csv(csvfile)
    nrow(file)
 }

This works when the ID argument is one number, say 17. But, if I input say 10:50 as an argument, I receive an error:

Error in file(file, "rt") : invalid 'description' argument

What should I do to be able to count the total number of rows from the inputed ID parameter?

Answer

Romain Francois picture Romain Francois · Jan 16, 2013

read.csv expects to read just one file, so you need to loop over files, a R idiomatic way of doing so is to use sapply:

nrows <- sapply( csvfile, function(f) nrow(read.csv(f)) )
sum(nrows)

For example, here is a rewrite of your complete function:

complete <- function(directory,id = 1:332) {
    csvfiles <- sprintf("/Users/gcameron/Desktop/%s/%03d.csv", directory, id)
    nrows <- sapply( csvfiles, function(f) nrow(read.csv(f)) )
    sum(nrows)
}