I have code like this:
ScrollView {
Image {
source: "..."
}
}
Image
is higher than the ScrollView
. How can I scroll the latter to the center of Image
element?
Despite the appearence, ScrollView
is tightly related to Flickable
. Indeed, Flickable
is used to control the visible area. Such an Item
is available as the (readonly
) property flickableItem
. Flickable
has the contentX
and contentY
properties to control the current visible area. These properties can be combined with the width
and height
of the ScrollView
to position the visible area exactly at the center. Typically you have:
flickableItem.contentY = flickableItem.contentHeight / 2 - height / 2
flickableItem.contentX = flickableItem.contentWidth / 2 - width / 2
The difference is necessary since the first calls just moves the center to the top left point of the visible area (where contentX
/contentY
are located).
Here is a complete example with an Image
as main child of the ScrollView
.
Disclaimer: In the simple scenario proposed by the example, with a remotelly loaded image, sizes can still be unset when onCompleted
is called, resulting in a centering code that doesn't work. By setting widths and heigths directly into code the problem is avoided. In a real scenario such detail should be unnecessary.
import QtQuick 2.4
import QtQuick.Window 2.2
import QtQuick.Controls 1.2
Window {
id: main
visible: true
width: 600; height: 350
ScrollView {
id: ss
width: 600
height: 350
Image {
id: name
width: 900
height: 600
source: "http://www.joomlaworks.net/images/demos/galleries/abstract/7.jpg"
}
Component.onCompleted: {
flickableItem.contentY = flickableItem.contentHeight / 2 - height / 2
flickableItem.contentX = flickableItem.contentWidth / 2 - width / 2
}
}
}