Calling parent class __init__ with multiple inheritance, what's the right way?

Adam Parkin picture Adam Parkin · Mar 6, 2012 · Viewed 89.8k times · Source

Say I have a multiple inheritance scenario:

class A(object):
    # code for A here

class B(object):
    # code for B here

class C(A, B):
    def __init__(self):
        # What's the right code to write here to ensure 
        # A.__init__ and B.__init__ get called?

There's two typical approaches to writing C's __init__:

  1. (old-style) ParentClass.__init__(self)
  2. (newer-style) super(DerivedClass, self).__init__()

However, in either case, if the parent classes (A and B) don't follow the same convention, then the code will not work correctly (some may be missed, or get called multiple times).

So what's the correct way again? It's easy to say "just be consistent, follow one or the other", but if A or B are from a 3rd party library, what then? Is there an approach that can ensure that all parent class constructors get called (and in the correct order, and only once)?

Edit: to see what I mean, if I do:

class A(object):
    def __init__(self):
        print("Entering A")
        super(A, self).__init__()
        print("Leaving A")

class B(object):
    def __init__(self):
        print("Entering B")
        super(B, self).__init__()
        print("Leaving B")

class C(A, B):
    def __init__(self):
        print("Entering C")
        A.__init__(self)
        B.__init__(self)
        print("Leaving C")

Then I get:

Entering C
Entering A
Entering B
Leaving B
Leaving A
Entering B
Leaving B
Leaving C

Note that B's init gets called twice. If I do:

class A(object):
    def __init__(self):
        print("Entering A")
        print("Leaving A")

class B(object):
    def __init__(self):
        print("Entering B")
        super(B, self).__init__()
        print("Leaving B")

class C(A, B):
    def __init__(self):
        print("Entering C")
        super(C, self).__init__()
        print("Leaving C")

Then I get:

Entering C
Entering A
Leaving A
Leaving C

Note that B's init never gets called. So it seems that unless I know/control the init's of the classes I inherit from (A and B) I cannot make a safe choice for the class I'm writing (C).

Answer

Raymond Hettinger picture Raymond Hettinger · Mar 6, 2012

Both ways work fine. The approach using super() leads to greater flexibility for subclasses.

In the direct call approach, C.__init__ can call both A.__init__ and B.__init__.

When using super(), the classes need to be designed for cooperative multiple inheritance where C calls super, which invokes A's code which will also call super which invokes B's code. See http://rhettinger.wordpress.com/2011/05/26/super-considered-super for more detail on what can be done with super.

[Response question as later edited]

So it seems that unless I know/control the init's of the classes I inherit from (A and B) I cannot make a safe choice for the class I'm writing (C).

The referenced article shows how to handle this situation by adding a wrapper class around A and B. There is a worked-out example in the section titled "How to Incorporate a Non-cooperative Class".

One might wish that multiple inheritance were easier, letting you effortlessly compose Car and Airplane classes to get a FlyingCar, but the reality is that separately designed components often need adapters or wrappers before fitting together as seamlessly as we would like :-)

One other thought: if you're unhappy with composing functionality using multiple inheritance, you can use composition for complete control over which methods get called on which occasions.