python: convert year/month/day/hour/min/second to # seconds since Jan 1 1970

Jason S picture Jason S · Dec 13, 2011 · Viewed 11.3k times · Source

I know how to do it in C and Java, but I don't know a quick way of converting year/month/day/hour/min/second to the # of seconds since the Jan 1 1970 epoch.

Can someone help me?

So far I've figured out how to create a datetime object but I can't seem to get the elapsed # seconds since the epoch.

(edit: my question is the inverse of this other one: Python: Seconds since epoch to relative date)

Answer

Anurag Uniyal picture Anurag Uniyal · Dec 13, 2011

Use timetuple or utctimetuple method to get time tuple and convert it to timestamp using time.mktime

>>> import datetime
>>> dt = datetime.datetime(2011, 12, 13, 10, 23)
>>> import time
>>> time.mktime(dt.timetuple())
1323793380.0

There is a nice bug related to it http://bugs.python.org/issue2736, this is interesting read and anybody trying to convert to timestamp should read this. According to that thread correct way is

timestamp = (dt - datetime(1970, 1, 1)) / timedelta(seconds=1)