I have this code (printing the occurrence of the all permutations in a string)
def splitter(str):
for i in range(1, len(str)):
start = str[0:i]
end = str[i:]
yield (start, end)
for split in splitter(end):
result = [start]
result.extend(split)
yield result
el =[];
string = "abcd"
for b in splitter("abcd"):
el.extend(b);
unique = sorted(set(el));
for prefix in unique:
if prefix != "":
print "value " , prefix , "- num of occurrences = " , string.count(str(prefix));
I want to print all the permutation occurrence there is in string varaible.
since the permutation aren't in the same length i want to fix the width and print it in a nice not like this one:
value a - num of occurrences = 1
value ab - num of occurrences = 1
value abc - num of occurrences = 1
value b - num of occurrences = 1
value bc - num of occurrences = 1
value bcd - num of occurrences = 1
value c - num of occurrences = 1
value cd - num of occurrences = 1
value d - num of occurrences = 1
How can I use format
to do it?
I found these posts but it didn't go well with alphanumeric strings:
I find using str.format
much more elegant:
>>> '{0: <5}'.format('s')
's '
>>> '{0: <5}'.format('ss')
'ss '
>>> '{0: <5}'.format('sss')
'sss '
>>> '{0: <5}'.format('ssss')
'ssss '
>>> '{0: <5}'.format('sssss')
'sssss'
If you want to align the string to the right use >
instead of <
:
>>> '{0: >5}'.format('ss')
' ss'
Edit 1:
As mentioned in the comments: the 0
in '{0: <5}'
indicates the argument’s index passed to str.format()
.
Edit 2: In python3 one could use also f-string:
sub_str='s'
for i in range(1,6):
s = sub_str*i
print(f'{s:>5}')
' s'
' ss'
' sss'
' ssss'
'sssss'
or:
for i in range(1,5):
s = sub_str*i
print(f'{s:<5}')
's '
'ss '
'sss '
'ssss '
'sssss'
of note, in some places above, ' '
(single quotation marks) were added to emphasize the width of the printed strings.