I'm seemingly unable to deserialize my MongoDB JSON document with the BSON json_util.
The json.loads function is choking on the ObjectId()
string. I had understood json_util capable of handling MongoDB's ObjectId format and transforming into usable JSON.
Python code:
import json
from bson import json_util
s = "{u'_id': ObjectId('4ed559abf047050c58000000')}"
u = json.loads(s, object_hook=json_util.object_hook)
I get the decoder exception:
...
u = json.loads(s, object_hook=json_util.object_hook)
File "\python27\lib\json\__init__.py", line 339, in loads
return cls(encoding=encoding, **kw).decode(s)
File "\python27\lib\json\decoder.py", line 366, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "\python27\lib\json\decoder.py", line 382, in raw_decode
obj, end = self.scan_once(s, idx)
ValueError: Expecting property name: line 1 column 1 (char 1)
Am I missing something?
I think your string form actually looks like the python representation...
s = '{"_id": {"$oid": "4edebd262ae5e93b41000000"}}'
u = json.loads(s, object_hook=json_util.object_hook)
print u # Result: {u'_id': ObjectId('4edebd262ae5e93b41000000')}
s = json.dumps(u, default=json_util.default)
print s # Result: {"_id": {"$oid": "4edebd262ae5e93b41000000"}}
The bson.json_util.object_hook function does not seem to have any type of handling for there being ObjectId() in the actual json string representation.