Unbounded range()

wim picture wim · Aug 25, 2011 · Viewed 8.9k times · Source

Is there an unbounded version of range (or xrange for Python 2), or is it necessary to define it manually? For example

squares = (x*x for x in range(n))

can only give me a generator for the squares up to (n-1)**2, and I can't see any obvious way to call range(infinity) so that it just keeps on truckin'.

Answer

Jeremy picture Jeremy · Aug 25, 2011

You're describing the basic use of itertools.count:

import itertools
squares = (x*x for x in itertools.count())