How to validate a url in Python? (Malformed or not)

python url malformedurlexception
Yugal Jindle picture Yugal Jindle · Aug 23, 2011 · Viewed 179.7k times · Source

I have url from the user and I have to reply with the fetched HTML.

How can I check for the URL to be malformed or not?

For example :

url='google'  // Malformed
url='google.com'  // Malformed
url='http://google.com'  // Valid
url='http://google'   // Malformed

Answer

Jabba picture Jabba · Aug 23, 2015

Use the validators package:

>>> import validators
>>> validators.url("http://google.com")
True
>>> validators.url("http://google")
ValidationFailure(func=url, args={'value': 'http://google', 'require_tld': True})
>>> if not validators.url("http://google"):
...     print "not valid"
... 
not valid
>>>

Install it from PyPI with pip (pip install validators).

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