Is there a more elegant way for unpacking keys and values of a dictionary into two lists, without losing consistence?

python list dictionary iterable-unpacking
Aufwind picture Aufwind · Jul 7, 2011 · Viewed 39.3k times · Source

What I came up with is:

keys, values = zip(*[(key, value) for (key, value) in my_dict.iteritems()])

But I am not satisfied. What do the pythonistas say?

Answer

FogleBird picture FogleBird · Jul 7, 2011 
keys, values = zip(*d.items())

Related questions

How to return dictionary keys as a list in Python?

In Python 2.7, I could get dictionary keys, values, or items as a list: >>> newdict = {1:0, 2:0, 3:0} >>> newdict.keys() [1, 2, 3] Now, in Python >= 3.3, I get something like this: >>> newdict.keys() dict_keys([1, 2, 3]) So, I …

Read More
How can I get list of values from dict?

How can I get a list of the values in a dict in Python? In Java, getting the values of a Map as a List is as easy as doing list = map.values();. I'm wondering if there is a similarly …

Read More
Convert two lists into a dictionary

Imagine that you have: keys = ['name', 'age', 'food'] values = ['Monty', 42, 'spam'] What is the simplest way to produce the following dictionary? a_dict = {'name' : 'Monty', 'age' : 42, 'food' : 'spam'}

Read More