Let's say I have a list like this:
mylist = [["A",0], ["B",1], ["C",0], ["D",2], ["E",2]]
How can I most elegantly group this to get this list output in Python:
[["A", "C"], ["B"], ["D", "E"]]
So the values are grouped by the secound value but the order is preserved...
values = set(map(lambda x:x[1], mylist))
newlist = [[y[0] for y in mylist if y[1]==x] for x in values]