Hello My error is produced in generating a zip file. Can you inform what I should do?
main.py", line 2289, in get
buf=zipf.read(2048)
NameError: global name 'zipf' is not defined
The complete code is as follows:
def addFile(self,zipstream,url,fname):
# get the contents
result = urlfetch.fetch(url)
# store the contents in a stream
f=StringIO.StringIO(result.content)
length = result.headers['Content-Length']
f.seek(0)
# write the contents to the zip file
while True:
buff = f.read(int(length))
if buff=="":break
zipstream.writestr(fname,buff)
return zipstream
def get(self):
self.response.headers["Cache-Control"] = "public,max-age=%s" % 86400
start=datetime.datetime.now()-timedelta(days=20)
count = int(self.request.get('count')) if not self.request.get('count')=='' else 1000
from google.appengine.api import memcache
memcache_key = "ads"
data = memcache.get(memcache_key)
if data is None:
a= Ad.all().filter("modified >", start).filter("url IN", ['www.koolbusiness.com']).filter("published =", True).order("-modified").fetch(count)
memcache.set("ads", a)
else:
a = data
dispatch='templates/kml.html'
template_values = {'a': a , 'request':self.request,}
path = os.path.join(os.path.dirname(__file__), dispatch)
output = template.render(path, template_values)
self.response.headers['Content-Length'] = len(output)
zipstream=StringIO.StringIO()
file = zipfile.ZipFile(zipstream,"w")
url = 'http://www.koolbusiness.com/list.kml'
# repeat this for every URL that should be added to the zipfile
file =self.addFile(file,url,"list.kml")
# we have finished with the zip so package it up and write the directory
file.close()
zipstream.seek(0)
# create and return the output stream
self.response.headers['Content-Type'] ='application/zip'
self.response.headers['Content-Disposition'] = 'attachment; filename="list.kmz"'
while True:
buf=zipf.read(2048)
if buf=="": break
self.response.out.write(buf)
That is probably zipstream
and not zipf
. So replace that with zipstream
and it might work.