I need a method to run a python script file, and if the script fails with an unhandled exception python should exit with a non-zero exit code. My first try was something like this:
import sys
if __name__ == '__main__':
try:
import <unknown script>
except:
sys.exit(-1)
But it breaks a lot of scripts, due to the __main__
guard often used. Any suggestions for how to do this properly?
Python already does what you're asking:
$ python -c "raise RuntimeError()"
Traceback (most recent call last):
File "<string>", line 1, in <module>
RuntimeError
$ echo $?
1
After some edits from the OP, perhaps you want:
import subprocess
proc = subprocess.Popen(['/usr/bin/python', 'script-name'])
proc.communicate()
if proc.returncode != 0:
# Run failure code
else:
# Run happy code.
Correct me if I am confused here.