Hello I'm trying to export a gmap html using ipywidgets in jupyter notebook but am encountering the following error: - error: bad escape \u at position 0.
I'm new to programing and could use help fixing whatever is causing this error to occur. If there is any easier way to go about exporting the html file I'm happy to change approaches.
Thanks
Here is a snippet of the code: I can add the entire thing if its helpful.
import pandas as pd
import gmaps
from ipywidgets.embed import embed_minimal_html
from ipywidgets import IntSlider
gmaps.configure(api_key='XXXX')
pd.options.mode.chained_assignment = None # default='warn'
file2 = '005 lat:long.csv'
state2 = pd.read_csv(file2)
state2 = state2.rename(columns={'Address1': 'address', 'City':'city',
'State':'state', 'Zip': 'zip'})
storenumbs = state2['Store'].str.split('#', expand=True)
state2 = state2.join(storenumbs)
state2 = state2.drop(['Store', 0], axis=1)
state2 = state2.rename(columns={1: 'store_#'})
state2['store_#'] = state2['store_#'].astype(int)
fig = gmaps.figure(center=(42.5, -71.4), map_type='TERRAIN', zoom_level=9.8)
scale = 4
one_layer = (gmaps.symbol_layer(low_points_lat_long, fill_color='red', stroke_color='red', scale= scale))
two_layer = (gmaps.symbol_layer(low_med_points_lat_long, fill_color='red', stroke_color='yellow', scale= scale))
three_layer = (gmaps.symbol_layer(med_high_points_lat_long, fill_color='yellow', stroke_color='green', scale= scale))
four_layer = (gmaps.symbol_layer(high_points_lat_long, fill_color='green', stroke_color='green', scale= scale))
fig.add_layer(one_layer)
fig.add_layer(two_layer)
fig.add_layer(three_layer)
fig.add_layer(four_layer)
fig
embed_minimal_html('export.html', views=[fig]
Long Form Error Bellow
)
KeyError Traceback (most recent call last)
~/miniconda3/lib/python3.7/sre_parse.py in parse_template(source, pattern)
1020 try:
-> 1021 this = chr(ESCAPES[this][1])
1022 except KeyError:
KeyError: '\\u'
During handling of the above exception, another exception occurred:
error Traceback (most recent call last)
<ipython-input-7-c096ac365396> in <module>
20
21 slider = IntSlider(value=40)
---> 22 embed_minimal_html('export.html', views=[slider], title='Widgets export')
~/miniconda3/lib/python3.7/site-packages/ipywidgets/embed.py in embed_minimal_html(fp, views, title, template, **kwargs)
300 {embed_kwargs}
301 """
--> 302 snippet = embed_snippet(views, **kwargs)
303
304 values = {
~/miniconda3/lib/python3.7/site-packages/ipywidgets/embed.py in embed_snippet(views, drop_defaults, state, indent, embed_url, requirejs, cors)
266 widget_views = u'\n'.join(
267 widget_view_template.format(view_spec=escape_script(json.dumps(view_spec)))
--> 268 for view_spec in data['view_specs']
269 )
270
~/miniconda3/lib/python3.7/site-packages/ipywidgets/embed.py in <genexpr>(.0)
266 widget_views = u'\n'.join(
267 widget_view_template.format(view_spec=escape_script(json.dumps(view_spec)))
--> 268 for view_spec in data['view_specs']
269 )
270
~/miniconda3/lib/python3.7/site-packages/ipywidgets/embed.py in escape_script(s)
239 involving `<` is readable.
240 """
--> 241 return script_escape_re.sub(r'\u003c\1', s)
242
243 @doc_subst(_doc_snippets)
~/miniconda3/lib/python3.7/re.py in _subx(pattern, template)
307 def _subx(pattern, template):
308 # internal: Pattern.sub/subn implementation helper
--> 309 template = _compile_repl(template, pattern)
310 if not template[0] and len(template[1]) == 1:
311 # literal replacement
~/miniconda3/lib/python3.7/re.py in _compile_repl(repl, pattern)
298 def _compile_repl(repl, pattern):
299 # internal: compile replacement pattern
--> 300 return sre_parse.parse_template(repl, pattern)
301
302 def _expand(pattern, match, template):
~/miniconda3/lib/python3.7/sre_parse.py in parse_template(source, pattern)
1022 except KeyError:
1023 if c in ASCIILETTERS:
-> 1024 raise s.error('bad escape %s' % this, len(this))
1025 lappend(this)
1026 else:
error: bad escape \u at position 0
This is an error in Python 3.7, and an issue with Python 3.6 (but it is OK with Python 2.7).
If you use a raw string (prefixed by "r") for the replacement in re.sub
function, then the \u
is escaped. For instance, r'\u003c\1'
is like '\\u003c\\1'
: this is a string '\u'
, followed by '003c'
and \1
.
The solution is to write:
return script_escape_re.sub('\u003c\\1', s)
Quoting the documentation:
Changed in version 3.7: Unknown escapes in repl consisting of
'\'
and an ASCII letter now are errors.