This seems trivial, but I cannot find a built-in or simple way to determine if two dictionaries are equal.
What I want is:
a = {'foo': 1, 'bar': 2}
b = {'foo': 1, 'bar': 2}
c = {'bar': 2, 'foo': 1}
d = {'foo': 2, 'bar': 1}
e = {'foo': 1, 'bar': 2, 'baz':3}
f = {'foo': 1}
equal(a, b) # True
equal(a, c) # True - order does not matter
equal(a, d) # False - values do not match
equal(a, e) # False - e has additional elements
equal(a, f) # False - a has additional elements
I could make a short looping script, but I cannot imagine that mine is such a unique use case.
==
works
a = dict(one=1, two=2, three=3)
b = {'one': 1, 'two': 2, 'three': 3}
c = dict(zip(['one', 'two', 'three'], [1, 2, 3]))
d = dict([('two', 2), ('one', 1), ('three', 3)])
e = dict({'three': 3, 'one': 1, 'two': 2})
a == b == c == d == e
True
I hope the above example helps you.