Text Scraping a PDF with Python (pdfquery)

Freya picture Freya · Oct 6, 2018 · Viewed 11.9k times · Source

I need to scrape some PDF files to extract the following text information:

enter image description here

I have attempted to do this using pdfquery, by working off an example I found on Reddit (see first post): https://www.reddit.com/r/Python/comments/4bnjha/scraping_pdf_files_with_python/

I wanted to test it out by getting the license numbers to start off with. I went into the generated "xmltree" file, found the first license number and got the x0,y0,x1,y1 co-ordinates in the LTTextLineHorizontal element.

import pdfquery
from lxml import etree


PDF_FILE = 'C:\\TEMP\\ad-4070-20-september-2018.pdf'

pdf = pdfquery.PDFQuery(PDF_FILE)
pdf.load(4,5)

with open('xmltree.xml','wb') as f:
    f.write(etree.tostring(pdf.tree, pretty_print=True))

product_info = []
page_count = len(pdf._pages)
for pg in range(page_count):
    data = pdf.extract([
        ('with_parent', 'LTPage[pageid="{}"]'.format(pg+1)),
        ('with_formatter', None),
        ('product_name', 'LTTextLineHorizontal:in_bbox("89.904, 757.502, 265.7, 770.83")'),
        ('product_details', 'LTTextLineHorizontal:in_bbox("223, 100, 737, 1114")'),
    ])
    for ix, pn in enumerate(sorted([d for d in data['product_name'] if d.text.strip()], key=lambda x: x.get('y0'), reverse=True)):
        product_info.append({'Manufacturer': pn.text.strip(), 'page': pg, 'y_start': float(pn.get('y1')), 'y_end': float(pn.get('y1'))-150})
        # if this is not the first product on the page, update the previous product's y_end with a
        # value slightly greater than this product's y coordinate start
        if ix > 0:
            product_info[-2]['y_end'] = float(pn.get('y0'))
    # for every product found on this page, find the detail information that falls between the
    # y coordinates belonging to the product
    for product in [p for p in product_info if p['page'] == pg]:
        details = []
        for d in sorted([d for d in data['product_details'] if d.text.strip()], key=lambda x: x.get('y0'), reverse=True):
            if  product['y_start'] > float(d.get('y0')) > product['y_end']:
                details.append(d.text.strip())
        product['Details'] = ' '.join(details)
pdf.file.close()

for p in product_info:
    print('Manufacturer: {}\r\nDetail Info:{}...\r\n\r\n'.format(p['Manufacturer'], p['Details'][0:100]))

However, when I run it, it doesn't print anything. There are no errors, the XML file generates fine, and I'm getting the co-ordinates straight from the XML file so there should be no issue. What am I doing wrong?

Answer

Roland Smith picture Roland Smith · Oct 6, 2018

For extracting text from a PDF file, my favorite tool is pdftotext.

Using the -layout option, you basically get a plain text back, which is relatively easy to manipulate using Python.

Example below:

"""Extract text from PDF files.

Requires pdftotext from the poppler utilities.
On unix/linux install them using your favorite package manager.

Binaries for ms-windows can be found at;
1) http://blog.alivate.com.au/poppler-windows/
2) https://sourceforge.net/projects/poppler-win32/
"""

import subprocess


def pdftotext(pdf, page=None):
    """Retrieve all text from a PDF file.

    Arguments:
        pdf Path of the file to read.
        page: Number of the page to read. If None, read all the pages.

    Returns:
        A list of lines of text.
    """
    if page is None:
        args = ['pdftotext', '-layout', '-q', pdf, '-']
    else:
        args = ['pdftotext', '-f', str(page), '-l', str(page), '-layout',
                '-q', pdf, '-']
    try:
        txt = subprocess.check_output(args, universal_newlines=True)
        lines = txt.splitlines()
    except subprocess.CalledProcessError:
        lines = []
    return lines