I'm confused about how to use asyncio.Queue
for a particular producer-consumer pattern in which both the producer and consumer operate concurrently and independently.
First, consider this example, which closely follows that from the docs for asyncio.Queue
:
import asyncio
import random
import time
async def worker(name, queue):
while True:
sleep_for = await queue.get()
await asyncio.sleep(sleep_for)
queue.task_done()
print(f'{name} has slept for {sleep_for:0.2f} seconds')
async def main(n):
queue = asyncio.Queue()
total_sleep_time = 0
for _ in range(20):
sleep_for = random.uniform(0.05, 1.0)
total_sleep_time += sleep_for
queue.put_nowait(sleep_for)
tasks = []
for i in range(n):
task = asyncio.create_task(worker(f'worker-{i}', queue))
tasks.append(task)
started_at = time.monotonic()
await queue.join()
total_slept_for = time.monotonic() - started_at
for task in tasks:
task.cancel()
# Wait until all worker tasks are cancelled.
await asyncio.gather(*tasks, return_exceptions=True)
print('====')
print(f'3 workers slept in parallel for {total_slept_for:.2f} seconds')
print(f'total expected sleep time: {total_sleep_time:.2f} seconds')
if __name__ == '__main__':
import sys
n = 3 if len(sys.argv) == 1 else sys.argv[1]
asyncio.run(main())
There is one finer detail about this script: the items are put into the queue synchronously, with queue.put_nowait(sleep_for)
over a conventional for-loop.
My goal is to create a script that uses async def worker()
(or consumer()
) and async def producer()
. Both should be scheduled to run concurrently. No one consumer coroutine is explicitly tied to or chained from a producer.
How can I modify the program above so that the producer(s) is its own coroutine that can be scheduled concurrently with the consumers/workers?
There is a second example from PYMOTW. It requires the producer to know the number of consumers ahead of time, and uses None
as a signal to the consumer that production is done.
How can I modify the program above so that the producer(s) is its own coroutine that can be scheduled concurrently with the consumers/workers?
The example can be generalized without changing its essential logic:
await producer()
or await gather(*producers)
, etc.await queue.join()
.Here is an example implementing the above:
import asyncio, random
async def rnd_sleep(t):
# sleep for T seconds on average
await asyncio.sleep(t * random.random() * 2)
async def producer(queue):
while True:
# produce a token and send it to a consumer
token = random.random()
print(f'produced {token}')
if token < .05:
break
await queue.put(token)
await rnd_sleep(.1)
async def consumer(queue):
while True:
token = await queue.get()
# process the token received from a producer
await rnd_sleep(.3)
queue.task_done()
print(f'consumed {token}')
async def main():
queue = asyncio.Queue()
# fire up the both producers and consumers
producers = [asyncio.create_task(producer(queue))
for _ in range(3)]
consumers = [asyncio.create_task(consumer(queue))
for _ in range(10)]
# with both producers and consumers running, wait for
# the producers to finish
await asyncio.gather(*producers)
print('---- done producing')
# wait for the remaining tasks to be processed
await queue.join()
# cancel the consumers, which are now idle
for c in consumers:
c.cancel()
asyncio.run(main())
Note that in real-life producers and consumers, especially those that involve network access, you probably want to catch IO-related exceptions that occur during processing. If the exception is recoverable, as most network-related exceptions are, you can simply catch the exception and log the error. You should still invoke task_done()
because otherwise queue.join()
will hang due to an unprocessed item. If it makes sense to re-try processing the item, you can return it into the queue prior to calling task_done()
. For example:
# like the above, but handling exceptions during processing:
async def consumer(queue):
while True:
token = await queue.get()
try:
# this uses aiohttp or whatever
await process(token)
except aiohttp.ClientError as e:
print(f"Error processing token {token}: {e}")
# If it makes sense, return the token to the queue to be
# processed again. (You can use a counter to avoid
# processing a faulty token infinitely.)
#await queue.put(token)
queue.task_done()
print(f'consumed {token}')