Convert Points to Lines Geopandas

Question

Hello I am trying to convert a list of X and Y coordinates to lines. I want to mapped this data by groupby the IDs and also by time. My code executes successfully as long as I grouby one column, but two columns is where I run into errors. I referenced to this question.

Here's some sample data:

ID  X           Y           Hour
1   -87.78976   41.97658    16
1   -87.66991   41.92355    16
1   -87.59887   41.708447   17
2   -87.73956   41.876827   16
2   -87.68161   41.79886    16
2   -87.5999    41.7083     16
3   -87.59918   41.708485   17
3   -87.59857   41.708393   17
3   -87.64391   41.675133   17

Here's my code:

df = pd.read_csv("snow_gps.csv", sep=';')

#zip the coordinates into a point object and convert to a GeoData Frame
geometry = [Point(xy) for xy in zip(df.X, df.Y)]
geo_df = GeoDataFrame(df, geometry=geometry)

# aggregate these points with the GrouBy
geo_df = geo_df.groupby(['track_seg_point_id', 'Hour'])['geometry'].apply(lambda x: LineString(x.tolist()))
geo_df = GeoDataFrame(geo_df, geometry='geometry')

Here is the error: ValueError: LineStrings must have at least 2 coordinate tuples

This is the final result I am trying to get:

ID          Hour     geometry
1           16       LINESTRING (-87.78976 41.97658, -87.66991 41.9... 
1           17       LINESTRING (-87.78964000000001 41.976634999999... 
1           18       LINESTRING (-87.78958 41.97663499999999, -87.6... 
2           16       LINESTRING (-87.78958 41.976612, -87.669785 41... 
2           17       LINESTRING (-87.78958 41.976624, -87.66978 41.... 
3           16       LINESTRING (-87.78958 41.97666, -87.6695199999... 
3           17       LINESTRING (-87.78954 41.976665, -87.66927 41.... 

Please any suggestions or ideas would be great on how to groupby multiple parameters.

Answer 1

Your code is good, the problem is your data.

You can see that if you group by ID and Hour, then there is only 1 point that is grouped with an ID of 1 and an hour of 17. A LineString has to consist of 1 or more Points (must have at least 2 coordinate tuples). I added another point to your sample data:

    ID   X          Y           Hour
    1   -87.78976   41.97658    16
    1   -87.66991   41.92355    16
    1   -87.59887   41.708447   17
    1   -87.48234   41.677342   17
    2   -87.73956   41.876827   16
    2   -87.68161   41.79886    16
    2   -87.5999    41.7083     16
    3   -87.59918   41.708485   17
    3   -87.59857   41.708393   17
    3   -87.64391   41.675133   17

and as you can see below the code below is almost identical to yours:

    import pandas as pd
    import geopandas as gpd
    from shapely.geometry import Point, LineString, shape

    df = pd.read_csv("snow_gps.csv", sep='\s*,\s*')

    #zip the coordinates into a point object and convert to a GeoData Frame
    geometry = [Point(xy) for xy in zip(df.X, df.Y)]
    geo_df = gpd.GeoDataFrame(df, geometry=geometry)

    geo_df2 = geo_df.groupby(['ID', 'Hour'])['geometry'].apply(lambda x:                 LineString(x.tolist()))
    geo_df2 = gpd.GeoDataFrame(geo_df2, geometry='geometry')