How do I get the path and name of the file that is currently executing?

python scripting file
Ray picture Ray · Sep 8, 2008 · Viewed 546.1k times · Source

I have scripts calling other script files but I need to get the filepath of the file that is currently running within the process.

For example, let's say I have three files. Using execfile:

  • script_1.py calls script_2.py.
  • In turn, script_2.py calls script_3.py.

How can I get the file name and path of script_3.py, from code within script_3.py, without having to pass that information as arguments from script_2.py?

(Executing os.getcwd() returns the original starting script's filepath not the current file's.)

Answer

user13993 picture user13993 · Dec 23, 2009 
__file__

as others have said. You may also want to use os.path.realpath to eliminate symlinks:

import os

os.path.realpath(__file__)

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