Custom weighted loss function in Keras for weighing each element

Nipun Batra picture Nipun Batra · Jan 3, 2018 · Viewed 18.4k times · Source

I'm trying to create a simple weighted loss function.

Say, I have input dimensions 100 * 5, and output dimensions also 100 * 5. I also have a weight matrix of the same dimension.

Something like the following:

import numpy as np
train_X = np.random.randn(100, 5)
train_Y = np.random.randn(100, 5)*0.01 + train_X

weights = np.random.randn(*train_X.shape)

Defining the custom loss function

def custom_loss_1(y_true, y_pred):
    return K.mean(K.abs(y_true-y_pred)*weights)

Defining the model

from keras.layers import Dense, Input
from keras import Model
import keras.backend as K

input_layer = Input(shape=(5,))
out = Dense(5)(input_layer)
model = Model(input_layer, out)

Testing with existing metrics works fine

model.compile('adam','mean_absolute_error')
model.fit(train_X, train_Y, epochs=1)

Testing with our custom loss function doesn't work

model.compile('adam',custom_loss_1)
model.fit(train_X, train_Y, epochs=10)

It gives the following stack trace:

InvalidArgumentError (see above for traceback): Incompatible shapes: [32,5] vs. [100,5]
 [[Node: loss_9/dense_8_loss/mul = Mul[T=DT_FLOAT, _device="/job:localhost/replica:0/task:0/device:CPU:0"](loss_9/dense_8_loss/Abs, loss_9/dense_8_loss/mul/y)]]

Where is the number 32 coming from?

Testing a loss function with weights as Keras tensors

def custom_loss_2(y_true, y_pred):
    return K.mean(K.abs(y_true-y_pred)*K.ones_like(y_true))

This function seems to do the work. So, probably suggests that a Keras tensor as a weight matrix would work. So, I created another version of the loss function.

Loss function try 3

from functools import partial

def custom_loss_3(y_true, y_pred, weights):
    return K.mean(K.abs(y_true-y_pred)*K.variable(weights, dtype=y_true.dtype))

cl3 = partial(custom_loss_3, weights=weights)  

Fitting data using cl3 gives the same error as above.

InvalidArgumentError (see above for traceback): Incompatible shapes: [32,5] vs. [100,5]
     [[Node: loss_11/dense_8_loss/mul = Mul[T=DT_FLOAT, _device="/job:localhost/replica:0/task:0/device:CPU:0"](loss_11/dense_8_loss/Abs, loss_11/dense_8_loss/Variable/read)]]

I wonder what I'm missing! I could have used the notion of sample_weight in Keras; but then I'd have to reshape my inputs to a 3d vector.

I thought that this custom loss function should really have been trivial.

Answer

rvinas picture rvinas · Jan 3, 2018

In model.fit the batch size is 32 by default, that's where this number is coming from. Here's what's happening:

  • In custom_loss_1 the tensor K.abs(y_true-y_pred) has shape (batch_size=32, 5), while the numpy array weights has shape (100, 5). This is an invalid multiplication, since the dimensions don't agree and broadcasting can't be applied.

  • In custom_loss_2 this problem doesn't exist because you're multiplying 2 tensors with the same shape (batch_size=32, 5).

  • In custom_loss_3 the problem is the same as in custom_loss_1, because converting weights into a Keras variable doesn't change their shape.


UPDATE: It seems you want to give a different weight to each element in each training sample, so the weights array should have shape (100, 5) indeed. In this case, I would input your weights' array into your model and then use this tensor within the loss function:

import numpy as np
from keras.layers import Dense, Input
from keras import Model
import keras.backend as K
from functools import partial


def custom_loss_4(y_true, y_pred, weights):
    return K.mean(K.abs(y_true - y_pred) * weights)


train_X = np.random.randn(100, 5)
train_Y = np.random.randn(100, 5) * 0.01 + train_X
weights = np.random.randn(*train_X.shape)

input_layer = Input(shape=(5,))
weights_tensor = Input(shape=(5,))
out = Dense(5)(input_layer)
cl4 = partial(custom_loss_4, weights=weights_tensor)
model = Model([input_layer, weights_tensor], out)
model.compile('adam', cl4)
model.fit(x=[train_X, weights], y=train_Y, epochs=10)