Reading specific partitions from a partitioned parquet dataset with pyarrow

suvayu picture suvayu · Dec 28, 2017 · Viewed 7.3k times · Source

I have a somewhat large (~20 GB) partitioned dataset in parquet format. I would like to read specific partitions from the dataset using pyarrow. I thought I could accomplish this with pyarrow.parquet.ParquetDataset, but that doesn't seem to be the case. Here is a small example to illustrate what I want.

To create a random dataset:

from collections import OrderedDict
from itertools import product, chain
from uuid import uuid4
import os
from glob import glob

import numpy as np
import pandas as pd
import pyarrow as pa
from pyarrow.parquet import ParquetWriter, ParquetDataset


def get_partitions(basepath, partitions):
    """Generate directory hierarchy for a paritioned dataset

    data
    ├── part1=foo
    │   └── part2=True
    ├── part1=foo
    │   └── part2=False
    ├── part1=bar
    │   └── part2=True
    └── part1=bar
        └── part2=False

    """
    path_tmpl = '/'.join(['{}={}'] * len(partitions))  # part=value
    path_tmpl = '{}/{}'.format(basepath, path_tmpl)    # part1=val/part2=val

    parts = [product([part], vals) for part, vals in partitions.items()]
    parts = [i for i in product(*parts)]
    return [path_tmpl.format(*tuple(chain.from_iterable(i))) for i in parts]


partitions = OrderedDict(part1=['foo', 'bar'], part2=[True, False])
parts = get_partitions('data', partitions)
for part in parts:
    # 3 columns, 5 rows
    data = [pa.array(np.random.rand(5)) for i in range(3)]
    table = pa.Table.from_arrays(data, ['a', 'b', 'c'])
    os.makedirs(part, exist_ok=True)
    out = ParquetWriter('{}/{}.parquet'.format(part, uuid4()),
                        table.schema, flavor='spark')
    out.write_table(table)
    out.close()

I want to read all values for partition one, and only True for partition 2. With pandas.read_parquet, that's not possible, I have to read the whole column always. I tried the following with pyarrow:

parts2 = OrderedDict(part1=['foo', 'bar'], part2=[True])
parts2 = get_partitions('data', parts2)
files = [glob('{}/*'.format(dirpath)) for dirpath in parts2]
files = [i for i in chain.from_iterable(files)]
df2 = ParquetDataset(files).read().to_pandas()

That doesn't work either:

>>> df2.columns
Index(['a', 'b', 'c'], dtype='object')

I can do this easily in pyspark like this:

def get_spark_session_ctx(appName):
    """Get or create a Spark Session, and the underlying Context."""
    from pyspark.sql import SparkSession
    spark = SparkSession.builder.appName(appName).getOrCreate()
    sc = spark.sparkContext
    return (spark, sc)


spark, sc = get_spark_session_ctx('test')
spark_df = spark.read.option('basePath', 'data').parquet(*parts2)
df3 = spark_df.toPandas()

As you can see below:

>>> df3.columns
Index(['a', 'b', 'c', 'part1', 'part2'], dtype='object')

Can this be done with pyarrow or pandas, or do I need some custom implementation?

Update: As requested by Wes, this is now on JIRA.

Answer

ji.xu picture ji.xu · Oct 2, 2018

As of pyarrow version 0.10.0 you can use filters kwarg to do the query. In your case it would look like something like this:

import pyarrow.parquet as pq
dataset = pq.ParquetDataset('path-to-your-dataset', filters=[('part2', '=', 'True'),])
table = dataset.read()

Ref