hog() got an unexpected keyword argument 'visualize'

SeanJ picture SeanJ · Oct 1, 2017 · Viewed 7.2k times · Source

I am running the scikit-image Histogram of Gradients example

The example code is as follows:

import matplotlib.pyplot as plt

from skimage.feature import hog
from skimage import data, color, exposure


image = color.rgb2gray(data.astronaut())

fd, hog_image = hog(image, orientations=8, pixels_per_cell=(16, 16),
                    cells_per_block=(1, 1), visualize=True)

fig, (ax1, ax2) = plt.subplots(1, 2, figsize=(8, 4), sharex=True, sharey=True)

ax1.axis('off')
ax1.imshow(image, cmap=plt.cm.gray)
ax1.set_title('Input image')
ax1.set_adjustable('box-forced')

# Rescale histogram for better display
hog_image_rescaled = exposure.rescale_intensity(hog_image, in_range=(0, 0.02))

ax2.axis('off')
ax2.imshow(hog_image_rescaled, cmap=plt.cm.gray)
ax2.set_title('Histogram of Oriented Gradients')
ax1.set_adjustable('box-forced')
plt.show()

Put simply, it does not work and reports the following error:

    fd, hog_image = hog(image, orientations=8, pixels_per_cell=(16, 16), cells_per_block=(1, 1), visualize=True)
TypeError: hog() got an unexpected keyword argument 'visualize'

I can view the astronaut image by commenting out the above section, so that is not the problem. Does anyone know why it is failing?

Answer

Lakshya Kejriwal picture Lakshya Kejriwal · Oct 1, 2017

It is a very small error but the spelling for your keyword argument visualize is wrong. It should be

fd, hog_image = hog(image, orientations=8, pixels_per_cell=(16, 16),
                cells_per_block=(1, 1), visualise=True)

Refer here for more information.