I have the following piece of code:
imgs = glob.glob('/home/chipin/heart/tray.png')
current_img = io.imread(imgs[0])
cv2.imwrite('/home/chipin/heart/01.png', current_img[0:511,0:511])
The size of picture is 512*512, after being saved, a blue picture turns yellow. It seems that a channel is abandoned. I really don't know why.
Here is the value of current_img:
Your problem is in the fact that skimage.io.imread
loads image as RGB (or RGBA), but OpenCV assumes the image to be BGR or BGRA (BGR is the default OpenCV colour format). This means that blue and red planes get flipped.
Let's try this out with the following simple test image:
First let's try your original algorithm:
import skimage.io
import cv2
img = skimage.io.imread('sample.png')
cv2.imwrite('sample_out_1.png', img)
We get the following result:
As you can see, red and blue channels are visibly swapped.
The first approach, assuming you want to still use skimage to read and cv2 to write is to use cv2.cvtColor
to convert from RGB to BGR.
Since the new OpenCV docs don't mention Python syntax, in this case you can also use the appropriate reference for 2.4.x.
import skimage.io
import cv2
img = skimage.io.imread('sample.png')
cv2.imwrite('sample_out_2.png', cv2.cvtColor(img, cv2.COLOR_RGB2BGR))
Now we get the following output:
An alternative is to just use OpenCV -- use cv2.imread
to load the image. In this case we're working only with BGR images.
NB: Not providing any flags means cv2.IMREAD_COLOR
is used by default -- i.e. image is always loaded as a 3-channel image (dropping any potential alpha channels).
import cv2
img = cv2.imread('sample.png')
cv2.imwrite('sample_out_3.png', img)
From your screenshot, it appears that you have a 4 channel image. This would mean RGBA in skimage, and BGRA in OpenCV. The principles would be similar.
cv2.COLOR_RGBA2BGRA
cv2.imread
with flag cv2.IMREAD_UNCHANGED