How to connect pyqtSignal
between two different objects (classes) PROPERLY? I mean best practice.
Look what I have done to achieve the goal: The Thermometer
class is notified when Pot
increases its temperature:
from PyQt4 import QtCore
class Pot(QtCore.QObject):
temperatureRaisedSignal = QtCore.pyqtSignal()
def __init__(self, parent=None):
super(Pot, self).__init__(parent)
self.temperature = 1
def Boil(self):
self.temperature += 1
self.temperatureRaisedSignal.emit()
def RegisterSignal(self, obj):
self.temperatureRaisedSignal.connect(obj)
class Thermometer():
def __init__(self, pot):
self.pot = pot
self.pot.RegisterSignal(self.temperatureWarning)
def StartMeasure(self):
self.pot.Boil()
def temperatureWarning(self):
print("Too high temperature!")
if __name__ == '__main__':
pot = Pot()
th = Thermometer(pot)
th.StartMeasure()
Or is there any easier / better way to do it?
I also insist (if possible) on using "new" style PyQt signals.
from PyQt4 import QtCore
class Pot(QtCore.QObject):
temperatureRaisedSignal = QtCore.pyqtSignal()
def __init__(self, parent=None):
QtCore.QObject.__init__(self)
self.temperature = 1
def Boil(self):
self.temperatureRaisedSignal.emit()
self.temperature += 1
class Thermometer():
def __init__(self, pot):
self.pot = pot
self.pot.temperatureRaisedSignal.connect(self.temperatureWarning)
def StartMeasure(self):
self.pot.Boil()
def temperatureWarning(self):
print("Too high temperature!")
if __name__ == '__main__':
pot = Pot()
th = Thermometer(pot)
th.StartMeasure()
This is how I would've done it according to the docs:
http://www.riverbankcomputing.com/static/Docs/PyQt4/html/new_style_signals_slots.html