I am using pycrypto module for AES encryption. And using documentation I have write down the below function but it al;ways gives error IV must be 16 bytes long
but I am using 16 byte long IV.
def aes_encrypt(plaintext):
"""
"""
key = **my key comes here**
iv = binascii.hexlify(os.urandom(16)) # even used without binascii.hexlify)
aes_mode = AES.MODE_CBC
obj = AES.new(key, aes_mode, iv)
ciphertext = obj.encrypt(plaintext)
return ciphertext
Use this:
from Crypto.Cipher import AES
import binascii,os
def aes_encrypt(plaintext):
key = "00112233445566778899aabbccddeeff"
iv = os.urandom(16)
aes_mode = AES.MODE_CBC
obj = AES.new(key, aes_mode, iv)
ciphertext = obj.encrypt(plaintext)
return ciphertext
Works as below:
>>> aes_encrypt("TestTestTestTest")
'r_\x18\xaa\xac\x9c\xdb\x18n\xc1\xa4\x98\xa6sm\xd3'
>>>
That's the difference:
>>> iv = binascii.hexlify(os.urandom(16))
>>> iv
'9eae3db51f96e53f94dff9c699e9e849'
>>> len(iv)
32
>>> iv = os.urandom(16)
>>> iv
'\x16fdw\x9c\xe54]\xc2\x12!\x95\xd7zF\t'
>>> len(iv)
16
>>>