Square root of complex numbers in python

CleptoMarcus picture CleptoMarcus · Apr 12, 2016 · Viewed 9.6k times · Source

I have run across some confusing behaviour with square roots of complex numbers in python. Running this code:

from cmath import sqrt
a = 0.2
b = 0.2 + 0j
print(sqrt(a / (a - 1)))
print(sqrt(b / (b - 1)))

gives the output

0.5j
-0.5j

A similar thing happens with

print(sqrt(-1 * b))
print(sqrt(-b))

It appears these pairs of statements should give the same answer?

Answer

tzaman picture tzaman · Apr 13, 2016

Both answers (+0.5j and -0.5j) are correct, since they are complex conjugates -- i.e. the real part is identical, and the imaginary part is sign-flipped.

Looking at the code makes the behavior clear - the imaginary part of the result always has the same sign as the imaginary part of the input, as seen in lines 790 and 793:

r.imag = copysign(d, z.imag);

Since a/(a-1) is 0.25 which is implicitly 0.25+0j you get a positive result; b/(b-1) produces 0.25-0j (for some reason; not sure why it doesn't result in 0.25+0j tbh) so your result is similarly negative.

EDIT: This question has some useful discussion on the same issue.