If a key is present in a dictionary, I want to know what position the key is in i.e the numerical index. For example :
if the dictionary consists of :
{'test':{1,3},'test2':{2},'test3':{2,3}}
if 'test' in dictionary:
print(the index of that key)
The output would be 0 for example. (The output would be 2 for 'test3'...)
I'm using a dictionary at the moment, I'm guessing I'd have to use an ordered dict
to do this, but how can I do it using an ordered dict
?
Thanks for any help.
For Python <3.6, you cannot do this because dictionaries in Python have no order to them, so items don't have an index. You could use an OrderedDict
from the collections
library instead though, and pass it a tuple of tuples:
>>> import collections
>>> d = collections.OrderedDict((('test',{1,3}),('test2',{2}),('test3',{2,3})))
>>> d.keys().index('test3') # Replace with list(d.keys()).index("test3") for Python 3
2