Is there a way to define the default/unprefixed namespace in python ElementTree? This doesn't seem to work...
ns = {"":"http://maven.apache.org/POM/4.0.0"}
pom = xml.etree.ElementTree.parse("pom.xml")
print(pom.findall("version", ns))
Nor does this:
ns = {None:"http://maven.apache.org/POM/4.0.0"}
pom = xml.etree.ElementTree.parse("pom.xml")
print(pom.findall("version", ns))
This does, but then I have to prefix every element:
ns = {"mvn":"http://maven.apache.org/POM/4.0.0"}
pom = xml.etree.ElementTree.parse("pom.xml")
print(pom.findall("mvn:version", ns))
Using Python 3.5 on OSX.
EDIT: if the answer is "no", you can still get the bounty :-). I just want a definitive "no" from someone who's spent a lot of time using it.
There is no straight-forward way to handle the default namespaces transparently. Assigning the empty namespace a non-empty name is a common solution, as you've already mentioned:
ns = {"mvn":"http://maven.apache.org/POM/4.0.0"}
pom = xml.etree.ElementTree.parse("pom.xml")
print(pom.findall("mvn:version", ns))
Note that lxml.etree
does not allow the use of empty namespaces explicitly. You would get:
ValueError
: empty namespace prefix is not supported in ElementPath
You can though, make things simpler, by removing the default namespace definition while loading the XML input data:
import xml.etree.ElementTree as ET
import re
with open("pom.xml") as f:
xmlstring = f.read()
# Remove the default namespace definition (xmlns="http://some/namespace")
xmlstring = re.sub(r'\sxmlns="[^"]+"', '', xmlstring, count=1)
pom = ET.fromstring(xmlstring)
print(pom.findall("version"))