How to remove '\x' from a hex string in Python?

Question

I'm reading a wav audio file in Python using wave module. The readframe() function in this library returns frames as hex string. I want to remove \x of this string, but translate() function doesn't work as I want:

>>> input = wave.open(r"G:\Workspace\wav\1.wav",'r')
>>> input.readframes (1)
'\xff\x1f\x00\xe8'
>>> '\xff\x1f\x00\xe8'.translate(None,'\\x')
'\xff\x1f\x00\xe8'
>>> '\xff\x1f\x00\xe8'.translate(None,'\x')
ValueError: invalid \x escape
>>> '\xff\x1f\x00\xe8'.translate(None,r'\x')
'\xff\x1f\x00\xe8'
>>> 

Any way I want divide the result values by 2 and then add \x again and generate a new wav file containing these new values. Does any one have any better idea?

What's wrong?

Answer 1

Indeed, you don't have backslashes in your string. So, that's why you can't remove them.

If you try to play with each hex character from this string (using ord() and len() functions - you'll see their real values. Besides, the length of your string is just 4, not 16.

You can play with several solutions to achieve your result: 'hex' encode:

'\xff\x1f\x00\xe8'.encode('hex')
'ff1f00e8'

Or use repr() function:

repr('\xff\x1f\x00\xe8').translate(None,r'\\x')