There are two directories on my desktop, DIR1
and DIR2
which contain the following files:
DIR1:
file1.py
DIR2:
file2.py myfile.txt
The files contain the following:
import sys
sys.path.append('.')
sys.path.append('../DIR2')
import file2
import sys
sys.path.append( '.' )
sys.path.append( '../DIR2' )
MY_FILE = "myfile.txt"
myfile = open(MY_FILE)
some text
Now, there are two scenarios. The first works, the second gives an error.
I cd
into DIR2
and run file2.py
and it runs no problem.
I cd
into DIR1
and run file1.py
and it throws an error:
Traceback (most recent call last):
File "<absolute-path>/DIR1/file1.py", line 6, in <module>
import file2
File "../DIR2/file2.py", line 9, in <module>
myfile = open(MY_FILE)
IOError: [Errno 2] No such file or directory: 'myfile.txt'
However, this makes no sense to me, since I have appended the path to file1.py
using the command sys.path.append('../DIR2')
.
Why does this happen when file1.py
, when file2.py
is in the same directory as myfile.txt
yet it throws an error? Thank you.
You can create a path relative to a module by using a module's __file__
attribute. For example:
myfile = open(os.path.join(
os.path.dirname(__file__),
MY_FILE))
This should do what you want regardless of where you start your script.