I have a tuple of tuples - for example:
tupleOfTuples = ((1, 2), (3, 4), (5,))
I want to convert this into a flat, one-dimensional list of all the elements in order:
[1, 2, 3, 4, 5]
I've been trying to accomplish this with list comprehension. But I can't seem to figure it out. I was able to accomplish it with a for-each loop:
myList = []
for tuple in tupleOfTuples:
myList = myList + list(tuple)
But I feel like there must be a way to do this with a list comprehension.
A simple [list(tuple) for tuple in tupleOfTuples]
just gives you a list of lists, instead of individual elements. I thought I could perhaps build on this by using the unpacking operator to then unpack the list, like so:
[*list(tuple) for tuple in tupleOfTuples]
or
[*(list(tuple)) for tuple in tupleOfTuples]
... but that didn't work. Any ideas? Or should I just stick to the loop?
it's typically referred to as flattening a nested structure.
>>> tupleOfTuples = ((1, 2), (3, 4), (5,))
>>> [element for tupl in tupleOfTuples for element in tupl]
[1, 2, 3, 4, 5]
Just to demonstrate efficiency:
>>> import timeit
>>> it = lambda: list(chain(*tupleOfTuples))
>>> timeit.timeit(it)
2.1475738355700913
>>> lc = lambda: [element for tupl in tupleOfTuples for element in tupl]
>>> timeit.timeit(lc)
1.5745135182887857
ETA: Please don't use tuple
as a variable name, it shadows built-in.