NameError: name 'argv' is not defined

Deborah Raquel Furr picture Deborah Raquel Furr · Aug 7, 2015 · Viewed 17.1k times · Source

I am trying to make a Google API call and am getting an error with the beginning of the code found here:

import os

import argparse
import sys

from apiclient import sample_tools
from oauth2client import client

# Declare command-line flags.
argparser = argparse.ArgumentParser(add_help=False)
argparser.add_argument(
    'profile_id', type=int,
    help='The ID of the profile to look up campaigns for')



  # Authenticate and construct service.
service, flags = sample_tools.init(
    argv[1:], 'dfareporting', 'v2.1', __doc__, os.path.abspath(os.path.dirname("__file__")), parents=[argparser],
    scope=['https://www.googleapis.com/auth/dfareporting',
           'https://www.googleapis.com/auth/dfatrafficking'])

if __name__ == '__main__':
  main(sys.argv)

However, the sample_tools.init function is not returning the service and flags object. I think I have isolated it to the argv argument a

NameError: name 'argv' is not defined

Any help would be much appreciated!!!

Answer

Padraic Cunningham picture Padraic Cunningham · Aug 7, 2015

You are missing sys:

sys.argv[1:]

You either need to from sys import argv and use argv everywhere or import sys as you have and use sys.argv. I also don't see a main function anywhere so main(sys.argv) is also going to cause a NameError