Passing all arguments of a function to another function

python function arguments
roopesh picture roopesh · Jun 29, 2010 · Viewed 35.4k times · Source

I want to pass all the arguments passed to a function(func1) as arguments to another function(func2) inside func1 This can be done with *args, *kwargs in the called func1 and passing them down to func2, but is there another way?

Originally

def func1(*args, **kwargs):
    func2(*args, **kwargs)

but if my func1 signature is 

def func1(a=1, b=2, c=3):

how do I send them all to func2, without using 

def func1(a=1, b=2, c=3):
    func2(a, b, c)

Is there a way as in javascript callee.arguments?

Answer

Jochen Ritzel picture Jochen Ritzel · Jun 29, 2010

Explicit is better than implicit but if you really don't want to type a few characters: 

def func1(a=1, b=2, c=3):
    func2(**locals())

locals() are all local variables, so you can't set any extra vars before calling func2 or they will get passed too.

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