How to parse timezone with colon

Question

Is there a way to parse timezone in "+00:00" format with datetime.strptime? For instance:

Python 3.4.3 (v3.4.3:9b73f1c3e601, Feb 24 2015, 22:43:06) [MSC v.1600 32 bit (In
tel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> from datetime import datetime
>>> datetime.strptime("12:34:56+0000", "%X%z")
datetime.datetime(1900, 1, 1, 12, 34, 56, tzinfo=datetime.timezone.utc)
>>> datetime.strptime("12:34:56+00:00", "%X%z")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Python34\lib\_strptime.py", line 500, in _strptime_datetime
    tt, fraction = _strptime(data_string, format)
  File "C:\Python34\lib\_strptime.py", line 337, in _strptime
    (data_string, format))
ValueError: time data '12:34:56+00:00' does not match format '%X%z'

Any ideas?

Answer 1

Currently, there is no cure for this, and here is and explanation: https://bugs.python.org/issue15873 more precisely, here: https://bugs.python.org/msg169952 . But you can override this issue, this way:

from datetime import datetime
d = "2015-04-30T23:59:59+00:00"
if ":" == d[-3:-2]:
    d = d[:-3]+d[-2:]
print(datetime.strptime(d, "%Y-%m-%dT%H:%M:%S%z"))