Python: TypeError: list indices must be integers, not list

python list loops indices
kotopanda picture kotopanda · Jun 17, 2015 · Viewed 28.1k times · Source

I've got two lists of coordinates, they look like this:

list_kp2_ok:

[[1185.60009765625, 933.6000366210938], [1310.4000244140625, 828.0000610351562], [1067.0, 979.0], [1310.0, 828.0], [1423.2000732421875, 814.800048828125], [1306.0, 828.0], [3634.0, 605.0], [1308.0960693359375, 827.7120971679688], [1422.7200927734375, 815.0400390625], [1185.1199951171875, 933.1200561523438], [1186.56005859375, 923.0400390625], [1306.3681640625, 829.4401245117188], [1194.393798828125, 839.80810546875], [1187.1361083984375, 922.7520751953125], [1082.8800048828125, 849.6000366210938]]

list_kp2_2_ok:

[[835.0, 1201.0], [1086.0, 850.0], [1187.0, 924.0], [1197.0, 839.0], [1310.0, 828.0], [3634.0, 605.0], [1195.2000732421875, 838.800048828125], [1308.0, 828.0000610351562], [1084.800048828125, 849.6000366210938], [1310.4000244140625, 828.0000610351562], [1186.800048828125, 924.0000610351562], [1296.0, 956.4000244140625], [1082.8800048828125, 849.6000366210938], [1072.800048828125, 944.6400146484375], [1083.4560546875, 850.1760864257812], [1187.1361083984375, 922.7520751953125], [3633.984375, 606.528076171875], [1082.4193115234375, 850.1761474609375], [1306.3681640625, 829.4401245117188], [1181.9521484375, 966.2977294921875], [1306.3682861328125, 828.6107788085938]]

Now I need to check if there are any same coordinates on both lists and create a new list of them. So I wrote:

list_wsp=[]
count=0
count1=0
print type(count)
print type(count1)
for count in list_kp2_ok:
    for count1 in list_kp2_2_ok:
        if list_kp2_ok[count]==list_kp2_2_ok[count1]:
            list_wsp.append(list_kp2_ok[count])
            count1=count1+1
            if count1==len(list_kp2_2_ok)-1:
                break
        count=count+1
        if count==len(list_kp2_ok)-1:
            break

and...

TypeError: list indices must be integers, not list

I don't know what's wrong, couldn't find a solution...

Could anyone help me, please?

Maybe there's a simplier way to do such a thing?

Answer

bruno desthuilliers picture bruno desthuilliers · Jun 17, 2015

Python's for loop is not indexed-based, it really iterates on the sequence (or any iterable). So in this code:

for whatever in some_iterable:
    do_something_with(whatever)

whatever is successively bound to each item in some_iterable. As an example:

>>> mylist = ["A", "B", "C"]
>>> for item in mylist:
...     print "item is", item
... 
item is A
item is B
item is C

If you want the indexes to, you can use the builtin enumerate(iterable, start=0) function, which yields a (index, item) tuple for each item in iterable:

>>> for index, item in enumerate(mylist):
...     print "item %s is %s" % (index, item)
... 
item 0 is A
item 1 is B
item 2 is C

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