Create a folder (if not exists) on google drive and upload a file to it using Python script

Akshay Kalghatgi picture Akshay Kalghatgi · Jun 2, 2015 · Viewed 10.9k times · Source

So far I can upload file to the folder if it exists. I can't figure out a way to create one though. So if the folder does not exist, my script dies.

import sys
from pydrive.auth import GoogleAuth
from pydrive.drive import GoogleDrive

gpath = '2015'
fname = 'Open Drive Replacements 06_01_2015.xls'

gauth = GoogleAuth()
gauth.LocalWebserverAuth()
drive = GoogleDrive(gauth)

file_list = drive.ListFile({'q': "'root' in parents and trashed=false"}).GetList()
for file1 in file_list:
    if file1['title'] == gpath:
        id = file1['id']

file1 = drive.CreateFile({'title': fname, "parents":  [{"kind": "drive#fileLink","id": id}]})
file1.SetContentFile(fname)
file1.Upload()

Can you please help me modify the above code to create folder gpath if it does not exist?

Answer

Gurupad Hegde picture Gurupad Hegde · Jun 2, 2015

Based on the documentation, it should be

file1 = drive.CreateFile({'title': fname, 
    "parents":  [{"id": id}], 
    "mimeType": "application/vnd.google-apps.folder"})

Update: As of Apr 2020, documentation (v3) has been updated with API docs and shows:

folder_id = '0BwwA4oUTeiV1TGRPeTVjaWRDY1E'
file_metadata = {
    'name': 'photo.jpg',
    'parents': [folder_id]
}
media = MediaFileUpload('files/photo.jpg',
                        mimetype='image/jpeg',
                        resumable=True)
file = drive_service.files().create(body=file_metadata,
                                    media_body=media,
                                    fields='id').execute()
print 'File ID: %s' % file.get('id')