I'm using the module openpyxl for Python and am trying to create a hyperlink that will take me to a different tab in the same Excel workbook. Doing something similar to the following creates the hyperlink; however, when I click on it, it tells me it can't open the file.
from openpyxl import Workbook
wb = Workbook()
first_sheet = wb.create_sheet(title='first')
second_sheet = wb.create_sheet(title='second')
first_sheet['A1'] = "hello"
second_sheet['B2'] = "goodbye"
link_from = first_sheet['A1']
link_to = second_sheet['B2'].value
link_from.hyperlink = link_to
wb.save("C:/somepath/workbook.xlsx")
I'm assuming the issue lies in the value of 'link_to'; however, I don't know what would need changed or what kind of path I would have to write.
I'm using Python 2.7.6 and Excel 2013.
I found a way to do it.
Assuming one .xlsx file named 'workbookEx.xlsx' with two sheets named 'sheet1' and 'sheet2' and needing a link from one cell(A1) of the 'sheet1' to another cell(E5) of the 'sheet2':
from openpyxl import load_workbook
wb = load_workbook(workbookEx.xlsx)
ws = wb.get_sheet_by_name("sheet1")
link = "workbookEx.xlsx#sheet2!E5"
ws.cell(row=1, column=1).hyperlink = (link)
The secret was the "#", Excel do not shows you but it uses the '#' for same file links, I just had to copy a same file link created in Excel to a Word document to see the '#'.
It is also possible to omit the filename, i.e. to link against a sheet of the active document just use: _cell.hyperlink = '#sheetName!A1'
.
To name the link you just created, just set the cell value to the desired string: _cell.value = 'Linkname'
.