How to calculate CRC32 with Python to match online results?

chronodekar picture chronodekar · May 7, 2015 · Viewed 85.7k times · Source

I'm trying to calculate/generate the CRC32 hash of some random strings using Python but they do not match the values I generate from online sources. Here is what I'm doing on my PC,

>>> import binascii
>>> binascii.crc32('hello-world')
-1311505829

Another approach,

>>> import zlib
>>> zlib.crc32('hello-world')
-1311505829

The fact that the above results are identical tells me that I'm calling the function correctly. But, if I go to the following online sources,

For the string "hello-world" they all give the same value = b1d4025b

Does anyone know what I need to do, to get matching results?

As I was typing this question it occurred to me that I might need to convert my Python result to hex,

>>> hex(zlib.crc32('hello-world'))
'-0x4e2bfda5'

Unfortunately, that hasn't helped either. :(

Answer

abarnert picture abarnert · May 7, 2015

Python 2 (unlike py3) is doing a signed 32-bit CRC.

Those sites are doing an unsigned 32-bit CRC.

The values are the same otherwise, as you can see from this:

>>> 0x100000000 - 0xb1d4025b == 0x4e2bfda5
True

One quick way to convert from 32-bit signed to 32-bit unsigned is:*

>>> -1311505829 % (1<<32)
2983461467

Or, in hex:

>>> hex(-1311505829 % (1<<32))
'0xb1d4025b'

& 0xFFFFFFFF or % 0x100000000 or & (2**32-1) or % (2**32) and so on are all equivalent ways to do the same bit-twiddling; it just comes down to which one you find most readable.


* This only works in languages that do floored integer division, like Python (-3 // 2 == -2); in languages that do truncated integer division, like Java (-3 / 2 == -1), you'll still end up with a negative number. And in languages that don't even require that division and mod go together properly, like C, all bets are off—but in C, you'd just cast the bytes to the type you want…