Python SQLite: database is locked

Soid picture Soid · Apr 29, 2010 · Viewed 132.1k times · Source

I'm trying this code:

import sqlite

connection = sqlite.connect('cache.db')
cur = connection.cursor()
cur.execute('''create table item
  (id integer primary key, itemno text unique,
        scancode text, descr text, price real)''')

connection.commit()
cur.close()

I'm catching this exception:

Traceback (most recent call last):
  File "cache_storage.py", line 7, in <module>
    scancode text, descr text, price real)''')
  File "/usr/lib/python2.6/dist-packages/sqlite/main.py", line 237, in execute
    self.con._begin()
  File "/usr/lib/python2.6/dist-packages/sqlite/main.py", line 503, in _begin
    self.db.execute("BEGIN")
_sqlite.OperationalError: database is locked

Permissions for cache.db are ok. Any ideas?

Answer

msw picture msw · Apr 29, 2010

I'm presuming you are actually using sqlite3 even though your code says otherwise. Here are some things to check:

  1. That you don't have a hung process sitting on the file (unix: $ fuser cache.db should say nothing)
  2. There isn't a cache.db-journal file in the directory with cache.db; this would indicate a crashed session that hasn't been cleaned up properly.
  3. Ask the database shell to check itself: $ sqlite3 cache.db "pragma integrity_check;"
  4. Backup the database $ sqlite3 cache.db ".backup cache.db.bak"
  5. Remove cache.db as you probably have nothing in it (if you are just learning) and try your code again
  6. See if the backup works $ sqlite3 cache.db.bak ".schema"

Failing that, read Things That Can Go Wrong and How to Corrupt Your Database Files