From the numpy documentation on logarithms, I have found functions to take the logarithm with base e, 2, and 10:
import numpy as np
np.log(np.e**3) #3.0
np.log2(2**3) #3.0
np.log10(10**3) #3.0
However, how do I take the logarithm with base n (e.g. 42) in numpy?
To get the logarithm with a custom base using math.log
:
import math
number = 74088 # = 42**3
base = 42
exponent = math.log(number, base) # = 3
To get the logarithm with a custom base using numpy.log
:
import numpy as np
array = np.array([74088, 3111696]) # = [42**3, 42**4]
base = 42
exponent = np.log(array) / np.log(base) # = [3, 4]
As you would expect, note that the default case of np.log(np.e) == 1.0
.
As a reminder, the logarithm base change rule is: