I am a student in a concepts of programming class. The lab is run by a TA and today in lab he gave us a real simple little program to build. It was one where it would multiply by addition. Anyway, he had us use absolute to avoid breaking the prog with negatives. I whipped it up real quick and then argued with him for 10 minutes that it was bad math. It was, 4 * -5 does not equal 20, it equals -20. He said that he really dosen't care about that and that it would be too hard to make the prog handle the negatives anyway. So my question is how do I go about this.
here is the prog I turned in:
#get user input of numbers as variables
numa, numb = input("please give 2 numbers to multiply seperated with a comma:")
#standing variables
total = 0
count = 0
#output the total
while (count< abs(numb)):
total = total + numa
count = count + 1
#testing statements
if (numa, numb <= 0):
print abs(total)
else:
print total
I want to do it without absolutes, but every time I input negative numbers I get a big fat goosegg. I know there is some simple way to do it, I just can't find it.
Perhaps you would accomplish this with something to the effect of
text = raw_input("please give 2 numbers to multiply separated with a comma:")
split_text = text.split(',')
a = int(split_text[0])
b = int(split_text[1])
# The last three lines could be written: a, b = map(int, text.split(','))
# but you may find the code I used a bit easier to understand for now.
if b > 0:
num_times = b
else:
num_times = -b
total = 0
# While loops with counters basically should not be used, so I replaced the loop
# with a for loop. Using a while loop at all is rare.
for i in xrange(num_times):
total += a
# We do this a times, giving us total == a * abs(b)
if b < 0:
# If b is negative, adjust the total to reflect this.
total = -total
print total
or maybe
a * b