replace special characters in a string python

Question

I am using urllib to get a string of html from a website and need to put each word in the html document into a list.

Here is the code I have so far. I keep getting an error. I have also copied the error below.

import urllib.request

url = input("Please enter a URL: ")

z=urllib.request.urlopen(url)
z=str(z.read())
removeSpecialChars = str.replace("!@#$%^&*()[]{};:,./<>?\|`~-=_+", " ")

words = removeSpecialChars.split()

print ("Words list: ", words[0:20])

Here is the error.

Please enter a URL: http://simleyfootball.com
Traceback (most recent call last):
  File "C:\Users\jeremy.KLUG\My Documents\LiClipse Workspace\Python Project 2\Module2.py", line 7, in <module>
    removeSpecialChars = str.replace("!@#$%^&*()[]{};:,./<>?\|`~-=_+", " ")
TypeError: replace() takes at least 2 arguments (1 given)

Answer 1

One way is to use re.sub, that's my preferred way.

import re
my_str = "hey th~!ere"
my_new_string = re.sub('[^a-zA-Z0-9 \n\.]', '', my_str)
print my_new_string

Output:

hey there

Another way is to use re.escape:

import string
import re

my_str = "hey th~!ere"

chars = re.escape(string.punctuation)
print re.sub(r'['+chars+']', '',my_str)

Output:

hey there

Just a small tip about parameters style in python by PEP-8 parameters should be remove_special_chars and not removeSpecialChars

Also if you want to keep the spaces just change [^a-zA-Z0-9 \n\.] to [^a-zA-Z0-9\n\.]