I am trying to plot the phasors of the voltage across the resistor, capacitor, and inductor in an series R-L-C circuit. I have done all of the calculations and I can get a decent plot with just the normal ax.plot(theta,r,....)
.
I would like to make the phasor vectors look like arrows. I have been trying to use ax.arrow(0,0,theta,magnitude)
but it looks like a line still. The gist to the code that I have written is here : GIST
I tried to follow the example that I found on this list because it is very similar to what I want to accomplish, it produces the following image:
When I run their code on my computer I get
I am on Xubuntu 14.04 and running matplotlib 1.3.1. I do see that the example I am using was using matplotlib 0.99 in 2009.
Any help would be much appreciated.
Arrow sizes were too big, this:
import matplotlib
import numpy as np
import matplotlib.pyplot as plt
print "matplotlib.__version__ = ", matplotlib.__version__
print "matplotlib.get_backend() = ", matplotlib.get_backend()
# radar green, solid grid lines
plt.rc('grid', color='#316931', linewidth=1, linestyle='-')
plt.rc('xtick', labelsize=15)
plt.rc('ytick', labelsize=15)
# force square figure and square axes looks better for polar, IMO
width, height = matplotlib.rcParams['figure.figsize']
size = min(width, height)
# make a square figure
fig = plt.figure(figsize=(size, size))
ax = fig.add_axes([0.1, 0.1, 0.8, 0.8], polar=True, axisbg='#d5de9c')
r = np.arange(0, 3.0, 0.01)
theta = 2*np.pi*r
ax.plot(theta, r, color='#ee8d18', lw=3)
ax.set_rmax(2.0)
plt.grid(True)
ax.set_title("And there was much rejoicing!", fontsize=20)
#This is the line I added:
arr1 = plt.arrow(0, 0.5, 0, 1, alpha = 0.5, width = 0.015,
edgecolor = 'black', facecolor = 'green', lw = 2, zorder = 5)
# arrow at 45 degree
arr2 = plt.arrow(45/180.*np.pi, 0.5, 0, 1, alpha = 0.5, width = 0.015,
edgecolor = 'black', facecolor = 'green', lw = 2, zorder = 5)
plt.show()
Produces:
Better? :)