Is there any clever in-built function or something that will return 1
for the min()
example below? (I bet there is a solid reason for it not to return anything, but in my particular case I need it to disregard None
values really bad!)
>>> max([None, 1,2])
2
>>> min([None, 1,2])
>>>
None
is being returned
>>> print min([None, 1,2])
None
>>> None < 1
True
If you want to return 1
you have to filter the None
away:
>>> L = [None, 1, 2]
>>> min(x for x in L if x is not None)
1